用过pycurl 模块的高手进来看一下

#utf-8
import pycurl
import StringIO
import urllib

url = "https://www.google.com/accounts/LoginAuth?continue=http%3A%2F%2Fwww.google.cn%2F&hl=zh-CN"
post_data_dic = {"pass":"123456","username":"guijia****"}
crl = pycurl.Curl()
crl.setopt(pycurl.VERBOSE,1)
crl.setopt(pycurl.FOLLOWLOCATION, 1)
crl.setopt(pycurl.MAXREDIRS, 5)
#crl.setopt(pycurl.AUTOREFERER,1)

crl.setopt(pycurl.CONNECTTIMEOUT, 60)
crl.setopt(pycurl.TIMEOUT, 300)
#crl.setopt(pycurl.PROXY,proxy)
crl.setopt(pycurl.HTTPPROXYTUNNEL,1)
#crl.setopt(pycurl.NOSIGNAL, 1)
crl.fp = StringIO.StringIO()
crl.setopt(pycurl.USERAGENT, "dhgu hoho")

# Option -d/--data <data>   HTTP POST data
crl.setopt(crl.POSTFIELDS,  urllib.urlencode(post_data_dic))

crl.setopt(pycurl.URL, url)

crl.setopt(crl.WRITEFUNCTION, crl.fp.write)

crl.setopt(pycurl.COOKIEJAR, "cookie_file_name")


crl.setopt(pycurl.COOKIEFILE, "cookie_file_name")

crl.perform()

print crl.fp.getvalue()

这个程序是登陆程序 我想如果登陆后进行下一步操作怎么办 打开下一个链接 好像没有打开不了 好像下一步的操作不能在用cr1这个对象进行操作了