请教 如何用python 发送html格式的email

请教 如何用python 发送html格式的email

此外 邮件内容 是string 变量，不是直接发送文件

你先了解一下mime multipart内容是怎么样的，再自己拼装。

现成的模块应该也有，不过就需要找了。

#!/usr/bin/env python
#-*- coding:utf-8 -*-

# Send an HTML email with an embedded image and a plain text message for
# email clients that don't want to display the HTML.

from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
from email.MIMEImage import MIMEImage

# Define these once; use them twice!
strFrom = 'xxxx'
strTo = 'xxxx'

# Create the root message and fill in the from, to, and subject headers
msgRoot = MIMEMultipart('related')
msgRoot['Subject'] = 'test message'
msgRoot['From'] = strFrom
msgRoot['To'] = strTo
msgRoot.preamble = 'This is a multi-part message in MIME format.'

# Encapsulate the plain and HTML versions of the message body in an
# 'alternative' part, so message agents can decide which they want to display.
msgAlternative = MIMEMultipart('alternative')
msgRoot.attach(msgAlternative)

msgText = MIMEText('This is the alternative plain text message.')
msgAlternative.attach(msgText)

# We reference the image in the IMG SRC attribute by the ID we give it below
msgText = MIMEText('<b>Some <i>HTML</i> text</b> and an image.<br><img src="cid:image1"><br>Nifty!', 'html','gbk')
msgAlternative.attach(msgText)

# This example assumes the image is in the current directory
fp = open('xxxx', 'rb')
msgImage = MIMEImage(fp.read())
fp.close()

# Define the image's ID as referenced above
msgImage.add_header('Content-ID', '<image1>')
msgRoot.attach(msgImage)

# Send the email (this example assumes SMTP authentication is required)
import smtplib
smtp = smtplib.SMTP()
smtp.set_debuglevel(1)
smtp.connect('smtp.xxx.com')
smtp.login('xxxxx', 'xxx')
smtp.sendmail(strFrom, strTo, msgRoot.as_string())