怎样在SOAP中返回对象？用ZSI

在ZSI中
用 wsdl2py 和 wsdl2dispatch 自动生成了一堆代码，但返回错误
不知道怎样才能用生成的代码返回一个object

aa_service_server.py

def soap_Query(self, ps):         self.request = ps.Parse(QueryRequest.typecode)         acc = self.request.Acc         # If we have an implementation object use it         if hasattr(self,'impl'):             parameters = self.impl.Query(acc)         result = QueryPasswordResponse()         #此处以上代码都好         #就是这个return，哎         return result

aa_services.py
......

QueryRequest = ns0.Query_Dec().pyclass QueryResponse = ns0.QueryResponse_Dec().pyclass

aa_services_types.py
.......

class QueryResponse_Dec(ElementDeclaration):         literal = "QueryResponse"         schema = "urn:GAME"         def __init__(self, **kw):             kw["pname"] = ("urn:GAME","QueryResponse")             kw["aname"] = "_QueryResponse"             if ns0.TQueryResponse_Def not in ns0.QueryResponse_Dec.__bases__:                 bases = list(ns0.QueryResponse_Dec.__bases__)                 bases.insert(0, ns0.TQueryResponse_Def)                 ns0.QueryResponse_Dec.__bases__ = tuple(bases)             ns0.TQueryResponse_Def.__init__(self, **kw)             if self.pyclass is not None: self.pyclass.__name__ = "QueryResponse_Dec_Holder"

还有其他相关的代码