大侠帮忙:一个模式匹配的问题

CODE:

#将所有[]里面的内容读到s1里面

s1 = re.compile('\[[^\]]*\]',re.S|re.M).findall(a)
dd = []
for  x in s1:
    x1 = re.compile('\<[^\>]*\>',re.S|re.M).sub('',x)  #将[]内的html标记（<>里面的内容）去掉
    dd.append(x1)

CODE:

ff = re.sub(s1[0],dd[0],a)
while i<len(s1):
    ff = re.sub(s1[i],dd[i],ff)
    print s1[i]
    print dd[i]
    i +=1
print ff

CODE:

for i in range(len(s1)):
    a = a.replace(s1[i], dd[i])
print a

CODE:

for i in range(len(s1)):
    a = re.sub(re.escape(s1[i]), dd[i], a)
print a

CODE:

#coding=cp936
import re

a ='<p>吖<span lang=EN-US> ā [</span>吖嗪<span lang=EN-US>] (ā</span>ｑ<span lang=EN-US>í</span>ｎ<span lang=EN-US>) '

def do_sub(m):
    return re.sub(r'<.*?>', '', m.group())
a = re.sub(r'\[.*?\]', do_sub, a)
print a

QUOTE:

*?, +?, ??

The "*", "+", and "?" qualifiers are all greedy; they match as much text as possible. Sometimes this behaviour isn't desired; if the RE <.*> is matched against '<H1>title</H1>', it will match the entire string, and not just '<H1>'. Adding "?" after the qualifier makes it perform the match in non-greedy or minimal fashion; as few characters as possible will be matched. Using .*? in the previous expression will match only '<H1>'.