print

hr_it

1^# hr_it 发表于 2008-10-25 13:00

print "The aswer is ",5*7,"\n";
$foo = "The aswer is ".5*7."\n";
print $foo;

刚看perl. 运行的时候老提示第2个有错误.

String found where operator expected at test line 5, near "7."\n""
(Missing operator before "\n"?)

why???

dl0622

2^# dl0622 发表于 2008-10-25 13:50

把5*7用引号引起来吧，可能原因是.号在前，优先于*号

ynchnluiti

3^# ynchnluiti 发表于 2008-10-25 13:51

. 连接字符串，也可能是浮点数中的.号。
如果7和.之间加个空格就对了，或者5*7加括号

hr_it

4^# hr_it 发表于 2008-10-25 15:03

谢谢楼上的解答.

khandielas

5^# khandielas 发表于 2008-10-26 08:15

Suggest you to read "Perl Best Practices". It is really a good book, well-written and very practical.