"1,2,3".split(",").each{|s| s = s.to_i}

rubylee

1^# rubylee 发表于 2008-01-15 15:15

"1,2,3".split(",").each{|s| s = s.to_i}

为什么不是[1, 2, 3]

caryl

2^# caryl 发表于 2008-01-15 16:10

"1,2,3".split(",").collect{|s| s.to_i}

rubylee

3^# rubylee 发表于 2008-01-16 10:40

噢 each只是遍历数组并返回原数组
而collect会返回处理后的数组

admin

4^# admin 发表于 2008-01-16 11:03

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rubylee

5^# rubylee 发表于 2008-01-16 13:14

嗯 map和collect貌似一样都会返回影响后的数组
但原数组都没有发生改变

我的意思是让原数组发生改变

xavier

6^# xavier 发表于 2008-01-16 16:35

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archangel_hzm

7^# archangel_hzm 发表于 2008-01-16 17:05

"1,2,3".split(",").map!{|s| s = s.to_i }

rubylee

8^# rubylee 发表于 2008-01-18 09:47

楼上正解

&quot;1,2,3&quot;.split(&quot;,&quot;).each{|s| s = s.to_i}